Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 106

Answer

$64\pi \text{ square inches}$

Work Step by Step

The variation model described by the problem is $ S=kr^2 ,$ where $ S $ is the surface area, and $ r $ is the radius. Substituting the known values in the variation model above results to \begin{array}{l}\require{cancel} 36\pi=k(3)^2 \\ 36\pi=k(9) \\ \dfrac{36\pi}{9}=k \\ k=4\pi .\end{array} Therefore, the variation equation is \begin{array}{l}\require{cancel} S=4\pi r^2 .\end{array} Using the variation equation above, then \begin{array}{l}\require{cancel} S=4\pi (4)^2 \\ S=4\pi (16) \\ S=64\pi .\end{array} Hence, the surface area, $S,$ is $ 64\pi \text{ square inches} .$
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