Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 71

Answer

$a=\dfrac{2A-hb}{h}$

Work Step by Step

By multiplying both sides by $ 2 $, the given equation, $ A=\dfrac{h(a+b)}{2} ,$ is equivalent to \begin{array}{l}\require{cancel} 2A=h(a+b) .\end{array} Using the properties of equality, then, in terms of $ a ,$ the equation above is equivalent to \begin{array}{l}\require{cancel} 2A=ha+hb \\\\ 2A-hb=ha \\\\ \dfrac{2A-hb}{h}=a \\\\ a=\dfrac{2A-hb}{h} .\end{array}
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