Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 81

Answer

$8 \text{ mph}$

Work Step by Step

Let $x$ be the rate of the current. Using $D=rt,$ then for upstream, \begin{array}{l}\require{cancel} 72=(32-x)t \\\\ \dfrac{72}{32-x}=t .\end{array} Using $D=rt,$ then for downstream, \begin{array}{l}\require{cancel} 120=(32+x)t \\\\ \dfrac{120}{32+x}=t .\end{array} Equating the two expressions of $t$ and using the properties of equality, then \begin{array}{l}\require{cancel} \dfrac{72}{32-x}=\dfrac{120}{32+x} \\\\ 72(32+x)=120(32-x) \\ 2304+72x=3840-120x \\ 72x+120x=3840-2304 \\ 192x=1536 \\ x=\dfrac{1536}{192} \\\\ x=8 .\end{array} Hence, the rate of the current, $x,$ is $ 8 \text{ mph} .$
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