Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 69

Answer

$x=\left\{-\dfrac{1}{3}, 2 \right\}$

Work Step by Step

Multiplying both sides by the $LCD= x^2 $, the value of the variable that satisfies the given equation, $ 3-\dfrac{5}{x}-\dfrac{2}{x^2}=0 ,$ is \begin{array}{l}\require{cancel} x^2(3)-x(5)-1(2)=x^2(0) \\\\ 3x^2-5x-2=0 \\\\ (3x+1)(x-2)=0 \\\\ x=\left\{-\dfrac{1}{3}, 2 \right\} .\end{array}
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