Answer
$\dfrac{1}{x-2}$
Work Step by Step
Adding the numerators and copying the common denominator, the given expression, $
\dfrac{2x+1}{x^2+x-6}+\dfrac{2-x}{x^2+x-6}
,$ simplifies to
\begin{array}{l}\require{cancel}
\dfrac{2x+1+2-x}{x^2+x-6}
\\\\=
\dfrac{x+3}{x^2+x-6}
\\\\=
\dfrac{x+3}{(x+3)(x-2)}
\\\\=
\dfrac{\cancel{x+3}}{(\cancel{x+3})(x-2)}
\\\\=
\dfrac{1}{x-2}
.\end{array}
