Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 405: 87

Answer

$\dfrac{3}{5x}$

Work Step by Step

The given expression, $ \dfrac{2}{5x}\div\dfrac{4-18x}{6-27x} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{2}{5x}\cdot\dfrac{6-27x}{4-18x} \\\\= \dfrac{2}{5x}\cdot\dfrac{3(2-9x)}{2(2-9x)} \\\\= \dfrac{\cancel{2}}{5x}\cdot\dfrac{3(\cancel{2-9x})}{\cancel{2}(\cancel{2-9x})} \\\\= \dfrac{3}{5x} .\end{array}
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