Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 62

Answer

$(x^3+2x^2-6) \text{ miles}$

Work Step by Step

Using $A=lw$ or the formula for the area of a rectangle, then \begin{array}{l}\require{cancel} A=lw \\ x^4-x^3-6x^2-6x+18=l(x-3) \\ \dfrac{x^4-x^3-6x^2-6x+18}{x-3}=l .\end{array} Using the long division method below, then \begin{array}{l}\require{cancel} l=\dfrac{x^4-x^3-6x^2-6x+18}{x-3} \\\\ l=x^3+2x^2-6 .\end{array} Hence, the length, $l,$ is $ (x^3+2x^2-6) \text{ miles} .$
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