Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 26

Answer

$10x^3(x+7)(x-4)(x-3)$

Work Step by Step

The given expressions are equivalent to \begin{array}{l}\require{cancel} \dfrac{1}{5x^3} ,\\\\ \dfrac{4}{(x+7)(x-4)} \text{ and ,} \\\\ \dfrac{11}{10x(x-3)} .\end{array} Hence, the $LCD$ of the given expressions is \begin{array}{l}\require{cancel} 10x^3(x+7)(x-4)(x-3) .\end{array}
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