Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 50

Answer

$4b+\frac{3}{b}$

Work Step by Step

Divide each term of the dividend by the divisor to have: $=\dfrac{12xb^2}{4xb^3}+\dfrac{16xb^4}{4xb^3} \\=\frac{3}{b}+4b$
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