Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 39

Answer

$\dfrac{5(4x-3)}{2(5x^2-2)}$

Work Step by Step

The given expression, $ \dfrac{2-\dfrac{3}{2x}}{x-\dfrac{2}{5x}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\dfrac{4x-3}{2x}}{\dfrac{5x^2-2}{5x}} \\\\= \dfrac{4x-3}{2x}\div\dfrac{5x^2-2}{5x} \\\\= \dfrac{4x-3}{2x}\cdot\dfrac{5x}{5x^2-2} \\\\= \dfrac{4x-3}{2\cancel{x}}\cdot\dfrac{5\cancel{x}}{5x^2-2} \\\\= \dfrac{5(4x-3)}{2(5x^2-2)} .\end{array}
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