Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 32

Answer

$\dfrac{2x^2-5x-4}{x-3}$

Work Step by Step

Using the $LCD= x-3 $, the given expression, $ 2x+1-\dfrac{1}{x-3} ,$ above simplifies to \begin{array}{l}\require{cancel} \dfrac{(x-3)(2x+1)-1(1)}{x-3} \\\\= \dfrac{2x^2+x-6x-3-1}{x-3} \\\\= \dfrac{2x^2-5x-4}{x-3} .\end{array}
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