Answer
$\dfrac{11}{x}$
Work Step by Step
Adding all the given dimensions, then the perimeter of the heptagon is
\begin{array}{l}\require{cancel}
\dfrac{3}{2x}+\dfrac{1}{x}+\dfrac{1}{x}+\dfrac{1}{x}+\dfrac{2}{x}+\dfrac{5}{2x}+\dfrac{2}{x}
\\\\=
\left( \dfrac{3}{2x}+\dfrac{5}{2x} \right)+\left(\dfrac{1}{x}+\dfrac{1}{x}+\dfrac{1}{x}+\dfrac{2}{x}+\dfrac{2}{x}\right)
\\\\=
\dfrac{8}{2x}+\dfrac{7}{x}
\\\\=
\dfrac{4}{x}+\dfrac{7}{x}
\\\\=
\dfrac{11}{x}
.\end{array}
