Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 41

Answer

$\dfrac{x(5y+1)}{3y}$

Work Step by Step

The given expression, $ \dfrac{\dfrac{5}{x}+\dfrac{1}{xy}}{\dfrac{3}{x^2}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{\dfrac{5y+1}{xy}}{\dfrac{3}{x^2}} \\\\= \dfrac{5y+1}{xy}\div\dfrac{3}{x^2} \\\\= \dfrac{5y+1}{xy}\cdot\dfrac{x^2}{3} \\\\= \dfrac{5y+1}{\cancel{x}y}\cdot\dfrac{\cancel{x}\cdot x}{3} \\\\= \dfrac{x(5y+1)}{3y} .\end{array}
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