Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 29

Answer

$\dfrac{3}{2(x-2)}$

Work Step by Step

Factoring the given expression, $ \dfrac{1}{x-2}-\dfrac{1}{4-2x} ,$ results to \begin{array}{l}\require{cancel} \dfrac{1}{x-2}-\dfrac{1}{2(2-x)} \\\\= \dfrac{1}{x-2}-\dfrac{1}{-2(x-2)} \\\\= \dfrac{1}{x-2}+\dfrac{1}{2(x-2)} .\end{array} Using the $LCD= 2(x-2) $, the expression above simplifies to \begin{array}{l}\require{cancel} \dfrac{2+1}{2(x-2)} \\\\= \dfrac{3}{2(x-2)} .\end{array}
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