Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 6 - Review - Page 404: 38

Answer

$\dfrac{x^3}{3(x+1)}$

Work Step by Step

The given expression, $ \dfrac{\dfrac{x^2}{15}}{\dfrac{x+1}{5x}} ,$ simplifies to \begin{array}{l}\require{cancel} \dfrac{x^2}{15}\div\dfrac{x+1}{5x} \\\\= \dfrac{x^2}{15}\cdot\dfrac{5x}{x+1} \\\\= \dfrac{x^2}{\cancel{5}\cdot3}\cdot\dfrac{\cancel{5}x}{x+1} \\\\= \dfrac{x^3}{3(x+1)} .\end{array}
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