Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 46

Answer

$a_6=6,250$

Work Step by Step

The geometric sequence $2,10,50,...$ has $a_1=2$ and $r=5$. Using $a_n=a_1r^{n-1}$, then the sixth term is \begin{array}{l} a_6=2(5)^{6-1} \\ a_6=2(3125) \\ a_6=6,250 .\end{array}
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