Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 13

Answer

$10\text{ percent}$

Work Step by Step

Substituting the known values in the given formula, $A=P(1+r)^t$, then, \begin{array}{l}\require{cancel} 2,420=2000(1+r)^2\\\\ \dfrac{2,420}{2000}=(1+r)^2\\\\ \dfrac{121}{100}=(1+r)^2\\\\ \sqrt{\dfrac{121}{100}}=1+r\\\\ \dfrac{11}{10}-1=r\\\\ r=\dfrac{1}{10} .\end{array} Hence, the rate of interest is $ 10\text{ percent} .$
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