Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review: 30c

Answer

$\dfrac{1}{5}$

Work Step by Step

Using the property $\ln e=1$ then the expression $ \ln\sqrt[5]{e} $ is equal to \begin{array}{l} \ln e^{1/5} \\= \dfrac{1}{5}(\ln e) \\= \dfrac{1}{5}(1) \\= \dfrac{1}{5} .\end{array}
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