## Intermediate Algebra (6th Edition)

Published by Pearson

# Chapter 11 - Cumulative Review: 24a

#### Answer

$7$

#### Work Step by Step

With $f(x)=x^2-2$ and $g(x)=x+1$, then, \begin{array}{l} (f\circ g)(2) \\= f(g(2)) \\= f(2+1) \text{...substitute $x=2$ in $g$} \\= f(3) \\= 3^2-2 \text{...substitute $x=3$ in $f$} \\= 7 .\end{array}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.