Answer
$7$
Work Step by Step
With $f(x)=x^2-2$ and $g(x)=x+1$, then,
\begin{array}{l}
(f\circ g)(2)
\\=
f(g(2))
\\=
f(2+1)
\text{...substitute $x=2$ in $g$}
\\=
f(3)
\\=
3^2-2
\text{...substitute $x=3$ in $f$}
\\=
7
.\end{array}
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