Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 26a

Answer

$x=5$

Work Step by Step

Using the properties of logarithms, then, \begin{array}{l} \log_2 32=x \\ \log_2 2^5=x \\ 5(\log_2 2)=x \\ 5(1)=x \\ x=5 .\end{array}
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