Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 44


$a_{8} = \frac{2}{3}$

Work Step by Step

Given, $a_{n} = \frac{n}{n+4}$ $a_{8} = \frac{8}{8+4} $ $a_{8} = \frac{8}{12}$ $a_{8} = \frac{2}{3}$
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