Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review - Page 670: 25b

Answer

$x=\dfrac{3}{2}$

Work Step by Step

Expressing both sides of the equal sign with the same base so that the exponents can be equated, then, \begin{array}{l} 9^x=27 \\ (3^2)^x=3^3 \\ 3^{2x}=3^3 \\ 2x=3 \\ x=\dfrac{3}{2} .\end{array}
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