## Intermediate Algebra (6th Edition)

$x=\dfrac{5}{3}$
Expressing the equation $8^x=32$ in the same base so that the exponents can be equated results to \begin{array}{l} (2^3)^x=2^5 \\ 2^{3x}=2^5 \\ 3x=5 \\ x=\dfrac{5}{3} .\end{array}