Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 11 - Cumulative Review: 28b

Answer

$x=\dfrac{5}{3}$

Work Step by Step

Expressing the equation $ 8^x=32 $ in the same base so that the exponents can be equated results to \begin{array}{l} (2^3)^x=2^5 \\ 2^{3x}=2^5 \\ 3x=5 \\ x=\dfrac{5}{3} .\end{array}
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