## Intermediate Algebra (6th Edition)

$x=\dfrac{\log7}{\log3}$
Taking the logarithm of both sides, then the values of $x$ in the equation $3^x=7$ is \begin{array}{l} \log3^x=\log7 \\ x(\log3)=\log7 \\ x=\dfrac{\log7}{\log3} .\end{array}