Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 42b

Answer

$(f\circ g)(x)=90$

Work Step by Step

Since $ (f\circ g)(-2)=f(g(-2)) $, then, \begin{array}{l} (f\circ g)(x)=f(-3(-2)+5) \\\\ (f\circ g)(x)=f(11) \\\\ (f\circ g)(x)=(11)^2-3(11)+2 \\\\ (f\circ g)(x)=90 \end{array}
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