Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review: 26

Answer

$\frac{(\sqrt 3-3)}{3}$

Work Step by Step

$\frac{-2}{\sqrt 3+3}\times\frac{\sqrt 3-3}{\sqrt 3-3}$ =$\frac{-2(\sqrt 3-3)}{(\sqrt 3+3)(\sqrt 3-3)}$ =$\frac{-2(\sqrt 3-3)}{(\sqrt 3)^{2}-(3)^{2}}$ =$\frac{-2(\sqrt 3-3)}{3-9}$ =$\frac{-2(\sqrt 3-3)}{-6}$ =$\frac{(\sqrt 3-3)}{3}$
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