Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 35b

Answer

$1$

Work Step by Step

Using $i^2=-1$, the expression $ i^{20} $ is equivalent to \begin{array}{l} (i^2)^{10} \\\\= (-1)^{10} \\\\= 1 \end{array}
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