Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 12

Answer

$\dfrac{5(a+2)}{3(a-5)(a+5)}$

Work Step by Step

The expression $ \dfrac{2}{3a-15}-\dfrac{a}{25-a^2} $ simplifies to \begin{array}{l} \dfrac{2}{3(a-5)}-\dfrac{a}{(5+a)(5-a)} \\\\= \dfrac{2}{3(a-5)}+\dfrac{a}{(5+a)(a-5)} \\\\= \dfrac{2(a+5)+3a}{3(a-5)(a+5)} \\\\= \dfrac{2a+10+3a}{3(a-5)(a+5)} \\\\= \dfrac{5a+10}{3(a-5)(a+5)} \\\\= \dfrac{5(a+2)}{3(a-5)(a+5)} .\end{array}
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