Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 13a

Answer

$\dfrac{1}{9xy^2}$

Work Step by Step

The expression $ \dfrac{\dfrac{2x}{27y^2}}{\dfrac{6x^2}{9}} $ simplifies to \begin{array}{l} \dfrac{2x}{27y^2}\div\dfrac{6x^2}{9} \\\\= \dfrac{2x}{27y^2}\cdot\dfrac{9}{6x^2} \\\\= \dfrac{18x}{162x^2y^2} \\\\= \dfrac{18x}{18x\cdot9xy^2} \\\\= \dfrac{1}{9xy^2} .\end{array}
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