Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 17

Answer

$P(4) = 16$

Work Step by Step

RECALL: The remainder when $P(x)$ is divided by $(x-c)$ is $P(c)$. Thus, when $P(x)=4x^6-25x^5+35x^4+17x^2$ is divided by $x-4$, the remainder is given by $P(4)$. Evaluate $P(4)$ to obtain: $P(4) = 4(4^6) - 25(4^5)+35(4^4)+17(4^2) \\P(4) = 16,384-25,600+8,960+272 \\P(4)=16$ Perform synthetic division to check if the remainder is really 16:
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