Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 24a

Answer

$2\sqrt{5}+5\sqrt{3}$

Work Step by Step

Using the Distributive Property and the properties of radicals the expression $ \sqrt{5}\left( 2+\sqrt{15} \right) $ is equivalent to \begin{array}{l} \sqrt{5}\cdot2+\sqrt{5}\cdot\sqrt{15} \\\\= 2\sqrt{5}+\sqrt{75} \\\\= 2\sqrt{5}+\sqrt{25\cdot3} \\\\= 2\sqrt{5}+5\sqrt{3} .\end{array}
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