Answer
$(f\circ g)(x)=9x^2-21x+12$
Work Step by Step
Since $
(f\circ g)(x)=f(g(x))
$, then,
\begin{array}{l}
(f\circ g)(x)=f(-3x+5)
\\\\
(f\circ g)(x)=(-3x+5)^2-3(-3x+5)+2
\\\\
(f\circ g)(x)=9x^2-30x+25+9x-15+2
\\\\
(f\circ g)(x)=9x^2+(-30x+9x)+(25-15+2)
\\\\
(f\circ g)(x)=9x^2-21x+12
\end{array}
