Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 10 - Cumulative Review - Page 634: 25b

Answer

$x^{2/3}-3x^{1/3}-10$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the FOIL Method and the properties of radicals, the expression $ (x^{1/3}-5)(x^{1/3}+2) $ is equivalent to \begin{array}{l} x^{1/3}(x^{1/3})+x^{1/3}(2)-5(x^{1/3})-5(2) \\\\= x^{\frac{1}{3}+\frac{1}{3}}+2x^{1/3}-5x^{1/3}-10 \\\\= x^{2/3}-3x^{1/3}-10 .\end{array}
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