Answer
$a=b=\sqrt2$
Work Step by Step
A counterexample is $a=b=\sqrt2$, where both $a$ and $b$ are irrational, but $ab=2$ is rational.
Elementary Linear Algebra 7th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
1-13311-087-8
ISBN 13:
978-1-13311-087-3
Appendix - Mathematical Induction and Other Forms of Proofs - Exercises - Page A6: 24
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