# Chapter 5 - Polynomials and Factoring - 5.4 Factoring Perfect-Square Trinomials and Differences of Squares - 5.4 Exercise Set - Page 333: 99

$7x^{2}-x+3$

#### Work Step by Step

The given expression, $(21x^3-3x^2+9x)\div(3x) ,$ simplifies to \begin{array}{l} \dfrac{21x^3}{3x}-\dfrac{3x^2}{3x}+\dfrac{9x}{3x} \\\\= 7x^{3-1}-1x^{2-1}+3x^{1-1} \\\\= 7x^{2}-1x^{1}+3x^{0} \\\\= 7x^{2}-1x^{1}+3(1) \\\\= 7x^{2}-x+3 \end{array}

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