## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$3t(5t+3)(5t-3)$
Factoring the $GCF= 3t$, the given expression, $75t^3-27t ,$ is equivalent to \begin{array}{l} 3t(25t^2-9) .\end{array} Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the expression, $3t(25t^2-9) ,$ is \begin{array}{l} 3t(5t+3)(5t-3) .\end{array}