# Chapter 5 - Polynomials and Factoring - 5.4 Factoring Perfect-Square Trinomials and Differences of Squares - 5.4 Exercise Set: 103

$(x^4+16)(x^2+4)(x+2)(x-2)$

#### Work Step by Step

Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the given expression, $x^8-2^8 ,$ is \begin{array}{l} (x^4+2^4)(x^4-2^4) \\\\= (x^4+2^4)(x^2+2^2)(x^2-2^2) \\\\= (x^4+2^4)(x^2+2^2)(x+2)(x-2) \\\\= (x^4+16)(x^2+4)(x+2)(x-2) \end{array}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.