Answer
$6(p+q)(p-q)$
Work Step by Step
Factoring the $GCF=
6
$, the given expression, $
6p^2-6q^2
,$ is equivalent to
\begin{array}{l}
6(p^2-q^2)
.\end{array}
Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the expression, $
6(p^2-q^2)
,$ is
\begin{array}{l}
6(p+q)(p-q)
.\end{array}
