## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 5 - Polynomials and Factoring - 5.4 Factoring Perfect-Square Trinomials and Differences of Squares - 5.4 Exercise Set - Page 333: 114

#### Answer

$(a^{2}+7b^{n})(a^{2}-7b^{n})$

#### Work Step by Step

Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the given expression, $a^{2n}-49b^{2n} ,$ is \begin{array}{l} (a^{2}+7b^{n})(a^{2}-7b^{n}) \end{array}

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