Answer
$5s^2(4s+3)(4s-3)$
Work Step by Step
Factoring the $GCF=
5s^2
$, the given expression, $
80s^4-45s^2
,$ is equivalent to
\begin{array}{l}
5s^2(16s^2-9)
.\end{array}
Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the expression, $
5s^2(16s^2-9)
,$ is
\begin{array}{l}
5s^2(4s+3)(4s-3)
.\end{array}