Answer
$2x\left( 3x+\dfrac{2}{5} \right)\left( 3x-\dfrac{2}{5} \right)$
Work Step by Step
Factoring $
2x
$, the given expression, $
18x^3-\dfrac{8}{25}x
,$ is equivalent to
\begin{array}{l}
2x\left( 9x^2-\dfrac{4}{25} \right)
.\end{array}
Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the expression, $
2x\left( 9x^2-\dfrac{4}{25} \right)
,$ is
\begin{array}{l}
2x\left( 3x+\dfrac{2}{5} \right)\left( 3x-\dfrac{2}{5} \right)
.\end{array}
