Answer
$2(7x+4y)(7x-4y)$
Work Step by Step
Factoring the $GCF=
2
$, the given expression, $
98x^2-32y^2
,$ is equivalent to
\begin{array}{l}
2(49x^2-16y^2)
.\end{array}
Using $x^2-y^2=(x+y)(x-y)$ or the factoring of the difference of 2 squares, then the factored form of the expression, $
2(49x^2-16y^2)
,$ is
\begin{array}{l}
2(7x+4y)(7x-4y)
.\end{array}