## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 95

#### Answer

$n\lt\dfrac{16}{3}$

#### Work Step by Step

The solution to the given expression, $8-2(n-7)\gt9-(3-n)$, is \begin{array}{l}\require{cancel} 8-2(n)-2(-7)\gt9-3+n \\\\ 8-2n+14\gt9-3+n \\\\ -2n-n\gt9-3-8-14 \\\\ -3n\gt-16 \\\\ n\lt\dfrac{-16}{-3} \\\\ n\lt\dfrac{16}{3} .\end{array}

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