Answer
$a^{8}b^{12}$
Work Step by Step
Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $
\dfrac{a^{10}b^{12}}{a^2b^0}
$, simplifies to
\begin{array}{l}\require{cancel}
a^{10-2}b^{12-0}
\\\\=
a^{8}b^{12}
.\end{array}
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 48
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