## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$9^{8}x^{8}$
$\displaystyle \frac{(9x)^{10}}{(9x)^{2}}\qquad$...apply The Quotient Rule $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=(9x)^{10-2}$ $=(9x)^{8}\qquad$...raise product to the $8$th power.$(ab)^{n}=a^{n}b^{n}$ $=9^{8}x^{8}$