Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 40

Answer

$9^{8}x^{8}$

Work Step by Step

$\displaystyle \frac{(9x)^{10}}{(9x)^{2}}\qquad$...apply The Quotient Rule $\displaystyle \frac{a^{m}}{a^{n}}=a^{m-n}$ $=(9x)^{10-2}$ $=(9x)^{8}\qquad$...raise product to the $8$th power.$(ab)^{n}=a^{n}b^{n}$ $=9^{8}x^{8}$
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