## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 80

#### Answer

$\dfrac{x^{35}}{y^{14}}$

#### Work Step by Step

Using $\left(\dfrac{a}{b}\right)^x=\dfrac{a^x}{b^x}$, then the expression, $\left(\dfrac{x^5}{y^2}\right)^7$, simplifies to \begin{array}{l}\require{cancel} \dfrac{(x^5)^7}{(y^2)^7} .\end{array} Using $(a^x)^y=a^{xy}$, then the given expression, $\dfrac{(x^5)^7}{(y^2)^7}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{x^{5(7)}}{y^{2(7)}} \\\\= \dfrac{x^{35}}{y^{14}} .\end{array}

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.