## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 77

#### Answer

$\dfrac{49}{36n^2}$

#### Work Step by Step

Using $\left(\dfrac{a}{b}\right)^x=\dfrac{a^x}{b^x}$, then the expression, $\left(\dfrac{7}{6n}\right)^2$, simplifies to \begin{array}{l}\require{cancel} \dfrac{7^2}{(6n)^2} \\\\= \dfrac{49}{(6n)^2} .\end{array} Using $(ab)^x=a^xb^x$, then the expression, $\dfrac{49}{(6n)^2}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{49}{6^2n^2} \\\\= \dfrac{49}{36n^2} .\end{array}

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