Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 71

Answer

$r^{17}t^{11}$

Work Step by Step

Using $(ab)^x=a^xb^x$, then the expression, $ (r^5t)^{3}(r^2t^8) $, simplifies to \begin{array}{l}\require{cancel} (r^{5(3)}t^{3})(r^2t^8) \\\\= (r^{15}t^{3})(r^2t^8) .\end{array} Using $a^x\cdot a^y=a^{x+y}$, then given expression, $ (r^{15}t^{3})(r^2t^8) $, simplifies to \begin{array}{l}\require{cancel} r^{15+2}t^{3+8} \\\\= r^{17}t^{11} .\end{array}
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