Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 43

Answer

$\dfrac{4d^{7}}{5}$

Work Step by Step

Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $ \dfrac{12d^9}{15d^2} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{3}\cdot4d^{9-2}}{\cancel{3}\cdot5} \\\\= \dfrac{4d^{7}}{5} .\end{array}
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