Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 67



Work Step by Step

Using $(ab)^x=a^xb^x$, then the expression, $ (-5n^7)^{2} $, simplifies to \begin{array}{l}\require{cancel} (-5)^2n^{7(2)} \\\\= 25n^{14} .\end{array}
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